Random strings in Python
How do you create a random string in Python?
I needed it to be number then character repeat till you're done this is what I created
def random_id(length):
number = '0123456789'
alpha = 'abcdefghijklmnopqrstuvwxyz'
id = ''
for i in range(0,length,2):
id += random.choice(number)
id += random.choice(alpha)
return id
Generating strings from (for example) lowercase characters:
import random, string
def randomword(length):
letters = string.ascii_lowercase
return ''.join(random.choice(letters) for i in range(length))
Results:
>>> randomword(10)
'vxnxikmhdc'
>>> randomword(10)
'ytqhdohksy'
Since this question is fairly, uh, random, this may work for you:
>>> import uuid
>>> print uuid.uuid4()
58fe9784-f60a-42bc-aa94-eb8f1a7e5c17
>>> import random
>>> import string
>>> s=string.lowercase+string.digits
>>> ''.join(random.sample(s,10))
'jw72qidagk
Answer to the original question:
os.urandom(n)
Quote from: http://docs.python.org/2/library/os.html
Return a string of n random bytes suitable for cryptographic use.
This function returns random bytes from an OS-specific randomness source. The returned data should be unpredictable enough for cryptographic applications, though its exact quality depends on the OS implementation. On a UNIX-like system this will query /dev/urandom, and on Windows it will use CryptGenRandom. If a randomness source is not found, NotImplementedError will be raised.
For an easy-to-use interface to the random number generator provided by your platform, please see random.SystemRandom.
You can build random ascii characters like:
import random
print chr(random.randint(0,255))
And then build up a longer string like:
len = 50
print ''.join( [chr(random.randint(0,255)) for i in xrange(0,len)] )
You haven't really said much about what sort of random string you need. But in any case, you should look into the random
module.
A very simple solution is pasted below.
import random
def randstring(length=10):
valid_letters='ABCDEFGHIJKLMNOPQRSTUVWXYZ'
return ''.join((random.choice(valid_letters) for i in xrange(length)))
print randstring()
print randstring(20)
random_name = lambda length: ''.join(random.sample(string.letters, length))
length must be <= len(string.letters) = 53. result example
>>> [random_name(x) for x in range(1,20)]
['V', 'Rq', 'YtL', 'AmUF', 'loFdS', 'eNpRFy', 'iWFGtDz', 'ZTNgCvLA', 'fjUDXJvMP', 'EBrPcYKUvZ', 'GmxPKCnbfih', 'nSiNmCRktdWZ', 'VWKSsGwlBeXUr', 'i
stIFGTUlZqnav', 'bqfwgBhyTJMUEzF', 'VLXlPiQnhptZyoHq', 'BXWATvwLCUcVesFfk', 'jLngHmTBtoOSsQlezV', 'JOUhklIwDBMFzrTCPub']
>>>
Enjoy. ;)
Sometimes, I've wanted random strings that are semi-pronounceable, semi-memorable.
import random
def randomWord(length=5):
consonants="bcdfghjklmnpqrstvwxyz"
vowels="aeiou"
return "".join(random.choice((consonants,vowels)[i%2]) for i in range(length))
Then,
>>> randomWord()
nibit
>>> randomWord()
piber
>>> randomWord(10)
rubirikiro
To avoid 4-letter words, don't set length
to 4.
Jim
Install this package:
pip3 install py_essentials
And use this code:
from py_essentials import simpleRandom as sr
print(sr.randomString(4))
More informations about the method other parameters are available here.
This function generates random string consisting of upper,lowercase letters, digits, pass the length seperator, no_of_blocks to specify your string format
eg: len_sep = 4, no_of_blocks = 4 will generate the following pattern,
F4nQ-Vh5z-JKEC-WhuS
Where, length seperator will add "-" after 4 characters
XXXX-
no of blocks will generate the following patten of characters as string
XXXX - XXXX - XXXX - XXXX
if a single random string is needed, just keep the no_of_blocks variable to be equal to 1 and len_sep to specify the length of the random string.
eg: len_sep = 10, no_of_blocks = 1, will generate the following pattern ie. random string of length 10,
F01xgCdoDU
import random as r
def generate_random_string(len_sep, no_of_blocks):
random_string = ''
random_str_seq = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
for i in range(0,len_sep*no_of_blocks):
if i % len_sep == 0 and i != 0:
random_string += '-'
random_string += str(random_str_seq[r.randint(0, len(random_str_seq) - 1)])
return random_string
import random
import string
def get_random_string(size):
chars = string.ascii_lowercase+string.ascii_uppercase+string.digits
''.join(random.choice(chars) for _ in range(size))
print(get_random_string(20)
output : FfxjmkyyLG5HvLeRudDS
참고URL : https://stackoverflow.com/questions/2030053/random-strings-in-python
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